Copyright © Philip M. Parker, INSEAD. Terms of Use.

(From Wikipedia, the free Encyclopedia)
Connectionss, parallel transport and curvature form the so-called golden triangle of Riemannian geometry. All three of these give equivalent structure - parallel transport is equivalent to specifying a covariant way of differentiating - or a connection; and a connection determines the curvature tensor.
The curvature tensor is given in terms of a connection (covariant differentiation) by the following formula:
The curvature tensor, on the other hand, via holonomy, determines parallel transport, although only up to a gauge.
There are several equivalent ways to think of the curvature tensor in the case of a Riemannian manifold. Perhaps the easiest way to understand it is as a linear transformation R of 2-forms.
To explain this, consider the sectional curvature, i.e. the curvature of a two-dimensional geodesic surface passing through a point - a section, which is the image of some tangent plane under the exponential map. The corresponding tangent plane can be represented by a 2-form. The curvature tensor gives information equivalent to specifying all sectional curvatures. The squared norm of a 2-form times the corresponding sectional curvature in fact gives a new quadratic form on a space of 2-forms, and it is given precisely by the symmetric linear operator R. In other words, (R(s),s)=k(s)(s,s).
The operator R can be understood in another way. Each 2-form s can be represented by a small rectangular loop (in many ways, but the corresponding form is what matters here). Then parallel transport around this loop gives rise to a transformation of the tangent space. This is a infinitesimal transformation of the tangent space, which can be represented by an element of the lie algebra corresponding to the lie group of all linear transformations of the tangent space. But this lie algebra is again an algebra of 2-forms, and R(s) is just this generator.
The lie algebra of all the loop transformations is the lie algebra of theholonomy corresponding to curvature.
Another way to represent curvature is as a (1,3)-valent tensor. In Riemannian geometry, valence of this tensor can be altered, and there are other equivalent representations of curvature.Golden triangle of Riemannian geometry
Various forms of curvature tensor on a Riemannian manifold
Source: the above text is adapted by the editor from Wikipedia, the free encyclopedia under a copyleft GNU Free Documentation License (GFDL) from the article "Curvature tensor."
Copyright © Philip M. Parker, INSEAD. Terms of Use.